A Hollywood daredevil plans to jump the canyon shown in the figure on a motorcyc

Question

A Hollywood daredevil plans to jump the canyon shown in the figure on a motorcycle. There is a 15. m drop and the horizontal distance originally planned was 60. m but it turns out the canyon is really 66.9 m across. If he desires a 2.8-second flight time, what is the correct angle for his launch ramp (deg)? What is his correct launch speed? What is the correct angle for his landing ramp (give a positive angle below the horizontal)? What is his predicted landing velocity? (Neglect air resistance.)

Explanation / Answer

http://www.cramster.com/answers-jun-11/physics/answer-hom-hollywood-daredevil-plans-jump-canyon-shown_1342861.aspx?rec=0

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