As shown in the figure above, mass mf = 2 kg is initially moving with a velocity
ID: 2020566 • Letter: A
Question
As shown in the figure above, mass mf = 2 kg is initially moving with a velocity v1,I = 5 m/s to the right with mass m2 = 4 kg initially at rest. Take the +x direction to point to the right and the +y direction to point up. The masses collide and immediately after the collosion mass m1 has a velocity of v1,f = 4 m/s at an angle of 30 degree below +x. Determine p2, fx, the x component of the final momentum for m2. P2, fy= kg.m/s. If the collision lasts for delta t = 3 times 10-5s, determine the magnitude of the average force Fave on m2. Fave = times 10 N. Under what condition(s) is (are) collisions considered elastic? Check to review before finishing (will be flagged in Table of Contents) A spring with spring constant k = 25 N/m is compressed a distance x = 0.1 m. A 50 g mass rests against one end of the spring. The other end of the spring is attached to the floor. When released, the mass is launched vertically into the air. What is the speed of the mass as it passes the equilibrium position for the spring (that is, the spring is no longer compressed nor stretched)? v = m/s If g = 10 m/s2 down, what is the maximum height the mass achieves? ymax = m Review Check to review before finishing (will be flagged in Table of Contents)Explanation / Answer
mass m = 50 g = 50*10-3 kg spring constant k = 25 N/m from conservation of energy , (1/2) kx2 = (1/2) mv2 v = {kx2 /m} = {(25 N/m)(0.1 m)2 /(50*10-3 kg)} = 2.236 m/s maximum height h = v2/2g = (2.236 m/s)2 / (2)(9.8 m/s2) = 0.25 m NOTE : As per cramster rules we shouldn't supposed to post more than one post for one time & The posted question seems to take longer time so, if it post seperetely , definetly we will helpful to u . As per cramster rules we shouldn't supposed to post more than one post for one time & The posted question seems to take longer time so, if it post seperetely , definetly we will helpful to u .Related Questions
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