Use the worked example above to help you solve this problem. A skier starts from
ID: 2020150 • Letter: U
Question
Use the worked example above to help you solve this problem. A skier starts from rest at the top of a frictionless incline of height 20.0 m, as shown in the figure. As the bottom of the incline, the skier encounters a horizontal surface where the coefficient of kinetic friction between skis and snow is 0.214.(a) Find the skier's speed at the bottom. = 19.8
(b) How far does the skier travel on the horizontal surface before coming to rest? = 93.6
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Use the values from PRACTICE IT to help you work this exercise. Find the horizontal distance the skier travels before coming to rest if the incline also has a coefficient of kinetic friction equal to 0.214. (The incline makes an angle ? = 20.0° with the horizontal.)
Explanation / Answer
from figure , sin = h/L length of the incline L = h/sin = (20 m) /sin20 = 58.476 m the coefficient of kinetic friction between skis and snow k = 0.214 speed v = {2gL(sin - k cos)} ={(2)(9.8 m/s2)(58.476 m)(sin20 - (0.214) cos20)} = 12.71 m/s then the distance travelled on the horizontal rough surface is d = v2/2g = (12.71 m/s) 2/ (2)(0.214)(9.8 m/s2) = 38.51 m then the distance travelled on the horizontal rough surface is d = v2/2g = (12.71 m/s) 2/ (2)(0.214)(9.8 m/s2) = 38.51 m then the distance travelled on the horizontal rough surface is d = v2/2g = (12.71 m/s) 2/ (2)(0.214)(9.8 m/s2) = 38.51 m then the distance travelled on the horizontal rough surface is d = v2/2g = (12.71 m/s) 2/ (2)(0.214)(9.8 m/s2) = 38.51 mRelated Questions
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