A 15.0 kg block is dragged over a rough, horizontal surface by a 95.0 N force ac

Question

A 15.0 kg block is dragged over a rough, horizontal surface by a 95.0 N force acting at 20.0° above the horizontal. The block is displaced 3.50 m, and the coefficient of kinetic friction is 0.300.
I need help with d. Once I have d, I can figure out e. a, b and c have been answered.
(a) Find the work done on the block by the 95.0 N force.
312 J
(b) Find the work done on the block by the normal force.
0 J
(c) Find the work done on the block by the gravitational force.
0 J

(d) What is increase in internal energy of the block-surface system due to friction?
answer in Joules
(e) Find the total change in the block's kinetic energy.
answer in Joules

Explanation / Answer

mass of the block m = 15 kg Applied force F = 95 N angle = 20 degrees displacment S = 3.5 m the coefficient of kinetic friction is = 0.300
(a) Find the work done on the block by the 95.0 N force.
312 J
(b) Find the work done on the block by the normal force.
0 J
(c) Find the work done on the block by the gravitational force 0 J (d). increase in internal energy of the block-surface system due to friction                                        = work done by frictional force                                        = [ frictional force * displacment ]                                        = [ mg - F sin ] * S                                        = 0.3 [ 147-32.49 ]*3.5                                       = 120.23 J

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