This is for my practice exam. I really want to be able to study from this exampl

Question

This is for my practice exam. I really want to be able to study from this example so if someone could answer it while writing out ALL of the steps you took and then the final answer i would REALLY appreciate it.

I have the first two parts. I just need someone to solve part 3. (c)



1. Two point charges are placed as follows:
[q1= +0.25 x 109C] at (1,0) and [q2= -2 x 10-9C] at (1, 3)

PART a.) What is the electric field (MAGNITUDE and DIRECTION) at the origin? Begin by drawing a diagram (please show the diagram!!) that shows schematically the placement of the charges and the direction of the electric field vectors at the origin due to each charge; use k = 9 x 109 Nm2/C2

answer: MAGNITUDE = 284 N/C; DIRECTION = 20.85 degrees

PART b.) What is the electric potential at the origin?

answer: 11.25 Volts


c.) If we assume the electric potential is 0 at infinity (that is, very far away), how much work has to be done to bring a charge of +1 C from very far away (infinity) to the origin?

THANK YOU IN ADVANCE. i dont even really know where to start for the third part.

Explanation / Answer

c) By the definetion of the potential difference, the work done in moving a charge of 1 C from infinity (electric potential is zero) to a point in the electric field is the potential difference between the two points. Therefore the work done in moving a cherge from infinity to a point in the field is W = Vq V is the potential difference q is the charge W = (0 V - 11.25 V)(1 C)      = (-11.25 V)(1*10-6 C)      = -11.25*10-6 J

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