Two spherical waves with the same amplitude, A, and wavelength, ?, are spreading

Question

Two spherical waves with the same amplitude, A, and wavelength, ?, are spreading out from two point sources S1 and S2 along one side of a barrier. The two waves have the same phase at positions S1 and S2. The two waves are superimposed at a position P. If the two waves interfere constructively at P what is the relationship between the path length difference dx=d2-d1 and the wavelength. If the two waves interfere destructively at P, what is the relationship between the path length difference and the wavelength?

Explanation / Answer

Two rays arriving at point P from the sources S1 and S2 . both being delivered from same amplitude , wave lengths (same wave front ) in the incident plane wave . Because the rays have different optical path lenghts. they arrive at P with a phase difference . the Number of wavelengths containde in S1b (path difference ) determines the Nature of the intreference at P     To get maximum brighteness (Constructive intererence )       condition: d sin = m             where : m = 0 , 1 ,2 ....       lly. for minimum (destructive intereference )          condition: d sin = (m + 1/2)         where: m = 0 , 1 , 2 ,3..... more over ,         the term , phase tells us what fraction of a           complete vibration the particle has executed at a given instant         phase differnce path difference                 (x2 - x1)                   = k (x2 - x1)                    = 2/ (x2 - x1)     Note: It may be helpful to u                

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