The circuit in the sketch has constant resistance 6.0 . The bar slides to the ri

Question

The circuit in the sketch has constant resistance 6.0 . The bar slides to the right on frictionless rails that are separated by 0.20 m. There is a uniform magnetic field B = 5.0 T directed out of the page. Electrical energy is being dissipated in the 6.0 at a rate of 24.0 W. What is the speed (v) of the bar?

*****Please provide ALL formulas/concepts used***The correct answer is 12 m/s...I have no clue on how to setup this problem, or even any formulas that could possibly help me find the speed***

Explanation / Answer

           induced emf on the bar = Blv ...............(1)         Here   magnetic field B=   5.0 T   , l = length of the bar   = 0.2m          power across the resistance   P   =  2 /R              Given     P   = 24.0W , Resistance   R = 6.0      Then      =   sqrt ( PR)   = 12 V                   From equation (1)                       velocity of the bar    v =   / Bl   =    12V / ( 5.0T * 0.2 m)   =   12 m/s

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