4) Billy Bob “Bubba” Hickman is working in his barn one day. He has a 25 kg hay

Question

4) Billy Bob “Bubba” Hickman is working in his barn one day. He has a 25 kg hay
bale suspended from the barn's rafters on a 2.44 meter long rope. Bubba pulls on
another rope horizontally until the rope holding
the hay bale makes an angle of 20 degrees with
respect to the vertical.
a) What force does Bubba have to exert on
the rope to hold the hay bale in this
position?
b) The rope slips out of Bubba's hands. The hay bale starts to swing. How
long does it take for the hay bale to swing to the farthest distance from
where it started (the farthest distance across the barn)?
c) Bubba runs to catch the hay bale. He tries to catch it at the bottom of the swing
as it swings back towards him. How fast is the hay bale moving when it hits
Bubba?

Explanation / Answer

A). Tcos20 = weight = 25kg(9.8) So T = 25(9.8)/cos20 T sin 20 = the force that bubba have to exert = 25(9.8)/cos20 x sin 20 = 25(9.8)tan 20 B)T = 2 pi sqr(l/g) = 2(3.14) x sqr(2.44/9.8) C) mgh= 1/2 mv^2 So v=sqr(2gh) = sqr(2 x 9.8 x (2.44 - 2.44cos20))

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