Bubba takes a uniform board of length L=1.34 m and a mass of 2.85 kg and nails t

Question

Bubba takes a uniform board of length L=1.34 m and a mass of 2.85 kg and nails three rounds objects into it. The first object has mass1=3.03 kg is nailed at a distance d1=17.6 cm from the left end of the board. Mass3=2.14 kg is nailed a distance3=11.6 cm from the right end of the board. Mass 2= 1.78 kg is nailed a distance of d2=26.3 cm from mass 3 (to the left). Determine the location of the center of mass of the entire system. Indicate from which end that you were measuring the center of mass.

Explanation / Answer

length of the board L = 1.34 m mass of the board M = 2.85 kg center of mass position of the board from left end  x = L / 2 = 0.67 m mass m1 = 3.03 kg distance of m1 from left end x1 = 17.6 cm = 0.176 m mass m3 = 2.14 kg distance of m3 from right end x ' = 11.6 cm = 0.116 m distance of m3 from left end x3 = 1.34 m - 0.116 m                                                 = 1.224 m mass m2= 1.78 kg distance of the m2 from left of m3 is x" = 26.3 cm =0.263 m distance of m2 from right end = 0.116 m + 0.263 m = 0.379 m distance of m2 from left end x2 = 1.34 m - 0.379 m = 0.961 m center of mass position X = [ Mx +m1x1+m2x2+m3x3 ] / [ M + m1+m2+m3]                                          = 0.691 m from left end

Related Questions

Navigate

• Browse (All)
• Browse B
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.