1) A 2.0 mm diameter iron ball is charged to +46 nC. What fraction of its electr
ID: 2017280 • Letter: 1
Question
1) A 2.0 mm diameter iron ball is charged to +46 nC. What fraction of its electrons have been removed? The density of iron is 7,870 kg/m3.2) The magnetic field of the brain has been measured to be approximately 3.1 10-12 T. Although the currents that cause this field are quite complicated, we can get a rough estimate of their size by modeling them as a single circular current loop 19 cm (the width of a typical head) in diameter. What current is needed to produce such a field at the center of the loop?
Explanation / Answer
Magnetic field of the brain = B = 3.1 x10-12 T single circular current loop with (the width of a typical head) in diameter = 19 cm d = 19 cm so, radious = r = 0.095 m Let , I be the current is needed to produce such a field at the center of the loop = ? It is known by the formual for magnetic field at the center of the circualr loop is B = o I / 2r where : o = 4 x10-7 A/m 3.1 x10-12 = 4 x10-7 ( I ) / 2 (0.095 ) 3.1 x10-12 = 66.1 (I ) I = 0.04689 x10-12 A * Please post first question seperately * * Please post first question seperately *Related Questions
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