Question 1.) Two weights are connected by a cable through a frictionless pulley

Question

Question 1.) Two weights are connected by a cable through a frictionless pulley as shown. If W1 = 10 N and W2 = 11 N, what is the equation for the velocity (in units of m/sec) of the W2 block assuming the weights are initially at rest?

Question 2.) Considering the system of weights as shown. If W2 is moving downward at a constant acceleration, which one of the following is correct? neglect air resistance:

a.) the tension in the cable equals W2

b.) the tension in the cable remains constant

c.) W2 acceleration is independent of the mass of W1

d.) the tension in the cable gradually decreases

Explain the reason for your choice

Explanation / Answer

Question 2: Let m1 is the mass of weight w1 and m2 is the mass of the weight w2. Here the weight w2 is moving downwards, then applying Newton's second law of motion we get            w2 - T = m2a ................ (1) Applying the Newton's second law to the weight w1 we get                T = m1a Substituting this value in the eq (1) we get            w2 - T = m2a            w2 - m1a = m2a             w2 = (m1 + m2)a               a = w2 / (m1 + m2) So acceleration of the w2 is independent of mass of w1. So correct option is (c). According to CRAMSTER's policy one question should be answered per each post. So please post the first question as separate. Then we will definitely help you.

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