1 Interphase (G2) CAK Mitosis Interphase (G Thr161- Tyr15-( Thr161-0 Wee1 Cdc25
ID: 201686 • Letter: 1
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1 Interphase (G2) CAK Mitosis Interphase (G Thr161- Tyr15-( Thr161-0 Wee1 Cdc25 cdc2 kinase cdc2 cdc2 kinase kinase Cyclin Inactive Post-mitotic fission Inactive G, fission yeast cell Inactive Cyclin Cyclin yeast cells Active Cyclin Degradation A scientists obtains a strain ofyeast with a temperature sensitive mutation that inactivates the function of Cdc25. He incubates wild type or the mutant strain at the permissive or restrictive temperature. He collects cells at different time points and runs a Western blot to detect the cyclin protein. Below are his results. Permissive Temperature 45 60 7590 105 0 15 30 cyclin mutant Restrictive Temperature 45 0 e) 15 30 60 75 90 1095 cyclin cdc25 mutant Describe and Interpret the results of this experiment and explain how they relate to the biological model shown.Explanation / Answer
Permissive temperature is the temperature at which the model will behave normally and the mutation will not be seen in the permissive temperature. So, on the first figure where both wild type and cdc-25 mutant have the same pattern is because at the permissive temperature the mutation will not take place as it is a temperature sensitive mutation. That is why after the one cycle on 30th minute cycling is getting degraded.
In restrictive temperature where the mutation will act then the CDC 25 will be inactivated and the cycling cdk complex will stick together and cycling will not be degraded and that is why in restrictive temperature the CDC 25 mutant will have cyclin bands irrespective of the time points.
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