A dielectric slab is slowly inserted between the paltes of a parallel-plate capa

Question

A dielectric slab is slowly inserted between the paltes of a parallel-plate capactiro, while the potential difference is held constant by a battery. As it is being inserted:

A. the capacitance, the potential difference between the plates, and the charge on the positve plate all increase
B.the capacitance, the potential difference between the plates, the charge on the postive palte decrease, and the capactiance remains the same.
C. the potential difference between the plate increases, the charge on the positve palte decreases, and capacitance remains the same
D. The capacitance and the charge on the positive plate decrease but the potential difference between the plates remain the same,
E. the capacitance and the charge on the postive palte increase but the potential difference between the paltes remain the same

Explanation / Answer

the capacitance and the charge on the plate increase but the potential difference between the plates remains the same. Because E didn't change and d didn't change and E=V/d.

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