Three particles are listed in the table. The mass and speed of each particle are

Question

Three particles are listed in the table. The mass and speed of each particle are given as multiples of the variables m and v, which have the values m = 1.77 10-8 kg and v = 0.200c. The speed of light in a vacuum is c = 3.00 108 m/s. Determine the momentum for each particle according to special relativity.
Particle Mass Speed Momentum

Please provide answers

Particle Mass Speed Momentum a m v   ---Select--- J/s m/s N kg · m/s J b m/2 2v   ---Select--- J/s m/s J N kg · m/s c m/4 4v   ---Select--- kg · m/s N m/s J J/s

Explanation / Answer

As per relativity formula, momentum,
p = [m0 /(1-(v/c)2)]*v
Thus,
for particle a, pa =[m/(1-(0.2)2)]*0.2c

= 0.204mc

= 1.08324 kg.m/s

for particle b,

pb =[0.5m/(1-(0.4)2)]*0.4c

= 0.218mc

=1.15758 kg.m/s

for particle c, pc =[0.25m/(1-(0.8)2)]*0.8c

= 0.333mc

= 1.76823 kg.m/s

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