a) 0.61 A b) 0.57A c) 0.94A d)0.86A e) 0.0A ( if you cant read the info it is: s
ID: 2014528 • Letter: A
Question
a) 0.61 A
b) 0.57A
c) 0.94A
d)0.86A
e) 0.0A
( if you cant read the info it is: starting from the left there is a 100V below that is the switch S. The resistor at the top is 25.0 Ohm and below that is a 15.0 uF capacitor. To the right of that capacitor is a 75.0 ohm resistor. The next to the bottom right of the 75.0 ohm resistor is a 20.0 uF capacitor. To the right of that capacitor is a 25.0 ohm resistor and all the way to the right is a 10 uF. On the bottom right of the circuit is a 25.0 ohm. To the left of that resistor is a 50.0 ohm resistor and all the way at the bottom is a 25.0 ohm resistor. Hopefully that clears things up)
2nd question relating to this circuit.
In the circuit above, the capacitors are all initially uncharged and the battery has no internal resistance. The reading on the ammeter long after the switch S is closed, is closest to:
a) 0.61A
b) 0.57A
c) 0.94A
d) 0.86A
e) 0.0A
Explanation / Answer
In both cases simplyfy the complicated circuit by eliminating the appropriate circuit elements the potential across a uncharged capacitor is initially zero. so it bahaves like a short circuit.A fully charged capacitor allows no current to flow through it . a) just after closing the switch the uncharged capacitors all behave loke short circuits , so any resistors in parallel with them are eliminated from the circuit S o the equivalent circuit consists of 50 and 25 in parallel with this combination is series with 75 , 15 and the 100 V battery the equivalent resistance is R = ( 75+15 ) + ( 1/ 50 ) + ( 1/ 25 ) = 90 + 16.6 7 = 106.67 reading on ammeter is I = 100 V / 106.7 = 0.937 A Answer is option ' C ' b) long after closing the swithc the capacitors are essentially charged up and behave like open circuits .since no charged can flow through them .they effectively eliminate any resistors in series with them no current can flow through these resistors the equivalent circuit consists of resistances 75 , 15 and three 25 resistors all in series with 100 V equivalent resistance is R = 75 + 15 + 25 + 25 + 25 = 165 current reading in the ammeter is I = 100 /165 = 0.606 A answer is option ' a ' = 106.67 reading on ammeter is I = 100 V / 106.7 = 0.937 A Answer is option ' C ' b) long after closing the swithc the capacitors are essentially charged up and behave like open circuits .since no charged can flow through them .they effectively eliminate any resistors in series with them no current can flow through these resistors the equivalent circuit consists of resistances 75 , 15 and three 25 resistors all in series with 100 V equivalent resistance is R = 75 + 15 + 25 + 25 + 25 = 165 current reading in the ammeter is I = 100 /165 = 0.606 A answer is option ' a 'Related Questions
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