1) Find the maximum magnitude of the acceleration. 2) Find the maximum magnitude
ID: 2013913 • Letter: 1
Question
1) Find the maximum magnitude of the acceleration.
2) Find the maximum magnitude of the velocity.
3)Find the acceleration when the pom-pom's coordinate is
A cheerleader waves her pom-pom in SHM with an amplitude of 17.9 cm and a frequency of 0.825 Hz . 1) Find the maximum magnitude of the acceleration. 2) Find the maximum magnitude of the velocity. 3)Find the acceleration when the pom-pom's coordinate is x= 9.00 cm . WHICH I FOUND TO BE = -2.42 m/s/s 4)Find the speed when the pom-pom's coordinate is x= 9.00 cm . 5)Find the time required to move from the equilibrium position directly to a point a distance 11.6 cm away. Anything will help, thank you.Explanation / Answer
amplitude A = 17.9 cm frequency f = 0.825 Hz the angulat speed = 2*f = 5.18 rad/s (1) the max acceleration = A^2 = 4.81 m/s^2 (2) the max velocity = A = 0.927 m/s (3) the acceleration a = ^2 (A^2- x^2)^1/2 = 41.51 m/s^2 (4) the speed V = (A^2- x^2)^1/2 = 8.01 m/s the time requared to move , t = 2(displace/ acceleratiom)^1/2Related Questions
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