moment of the loop. (b) What is the magnitude of the torque acting on the loop?

Question

moment of the loop. (b) What is the magnitude of the torque acting on the loop? A circular coil of 160 turns has a radius of 1.90 cm (a) Calculate the current that results in a magnetic dipole moment of magnitude 2.30 Am2. (b) Find the maximum magnitude of the torque that the coil, carrying this current. can experience in a uniform 35.0 mT magnetic field. The magnetic dipole moment of Earth has magnitude 8.00 times 1022 J/T. Assume that this is produced by charges flowing in Earth's molten outer core. If the radius of their circular path is 3500 km, calculate the current they produce. A current loop, carrying a current of 5.0 A. is in the shape of a right triangle with sides 30, 40, and 50 cm. The loop is in a uniform magnetic held of magnitude 80 m T whose direction is parallel to the current in the 50cm side of the Find the magnitude of (a) the magnetic dipole moment on the loop.

Explanation / Answer

magnetic dipole moment = 8*10^22 J/T = iA Here   current   i   =   / A A area of the circular path    =   r^2 = ( 3500 *10^3) ^2   = 3846.5*10^10 m^2 plug   the values current   I = (8*10^22 J/T )   / ( 3846.5*10^10 m^2 )   = 2.07*10^9 A

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