A Nichrome wire 75 cm long and 0.25 mm in diameter is connected to a 1.7 volt fl

Question

A Nichrome wire 75 cm long and 0.25 mm in diameter is connected to a 1.7 volt flashlight battery. What is the electric field inside the wire? Next, the Nichrome wire is replaced by a wire of the same length and diameter, and same mobile electron density but with electron mobility 4 tunes as large as that of Nichrome. Now what is the electric field inside the wire? The electron current in the first circuit (Nichrome) is i1. The electron current in the second circuit (wire with higher mobility ) is i2. Which of the following statements is true? i2 = i1 i2 i1 Not enough information is given to compare the two currents

Explanation / Answer

Data: Length, L = 0.75 m Diameter, D = 0.25 mm Radius, r = D / 2                  = 0.125 mm                  = 125 x 10^-6 m Voltage, V = 1.7 V Solution: (a) Electric field, E = V / L                              = 1.7 / 0.75                              = 2.26 V/m Ans: Electric field, E = 2.26 V/m (b) Electric field is independent of electron mobility. So, the electric field remains same. Ans: Electric field, E = 2.26 V/m (c) The electron current would increase due to more electron mobility. Ans: Option-3: i2 > i1

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