(a) Calculate the wavelength of light in vacuum that has a frequency of 4.2 *10^

Question

(a) Calculate the wavelength of light in vacuum that has a frequency of 4.2 *10^5 Hz.
Your answer is correct. 714.28 m.

(b) What is its wavelength in glycerine? (The index of refraction of glycerine is 1.473.)
Your answer is correct. 484.76 m.

(c) Calculate the energy of one photon of such light in vacuum. Express the answer in electron volts.

answer is in eV

(d) What is the properties of and effect on the energy of the photon when it enters the glycerine? (Select all that apply.)

-the energy is inversely proportional to the frequency
-the energy goes up
-the energy is proportional to the frequency
-the energy goes down
-the energy does not change
-the energy is not proportional to the frequency

I NEED ANSWER TO C AND D

Explanation / Answer

c) The frequency of the light in vacuum is f = 4.2*105 Hz The energy of the photon of such ligght is E = hf h = 6.626*10-34 Js is the Plank's constant E = (6.626*10-34 Js)(4.2*105 Hz) E = 2.78*10-28 J E = 2.78*10-28 J/1.6*10-19 J/eV E = 1.739*10-9 eV d) As the frequency does not change due to the medium, the energy proportional to frequency and does not change c) The frequency of the light in vacuum is f = 4.2*105 Hz The energy of the photon of such ligght is E = hf h = 6.626*10-34 Js is the Plank's constant E = (6.626*10-34 Js)(4.2*105 Hz) E = 2.78*10-28 J E = 2.78*10-28 J/1.6*10-19 J/eV E = 1.739*10-9 eV d) As the frequency does not change due to the medium, the energy proportional to frequency and does not change

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