A negative charge moving parallel to a 2 T magnetic field experienced a force of

Question

A negative charge moving parallel to a 2 T magnetic field experienced a force of 5 µN.

Which one of the following best explains why the above statement is false?



W = (Fcos?)s where ? is the angle between the force and the velocity. If the charge is moving parallel to the magnetic field then the angle between the velocity & the force is 90o and cos(90o) is 0. Thus no work is done and as a result there must be no force on the charge.

The magnetic field must always be perpendicular to the velocity.

µN is not a unit of force.

Magnetic fields make charges move in circles so the charge couldn't be moving in a straight line.

F = qvBsin? where ? is the angle between the velocity and the magnetic field. If the charge is moving parallel to the magnetic field then the angle between them is 0o, sin0o is 0, and the force is 0 N.

Negative charges can't have a magnetic force exerted on them because they aren't metals.

Explanation / Answer

F = q v X B , = q v B sin ;

since magnetic field is parrallel to velocity , so sin = 0 , so

F = q v B * 0 = 0 ,   so the force exerted will be zero .

F = qvBsin where is the angle between the velocity and the magnetic field. If the charge is moving parallel to the magnetic field then the angle between them is 0o, sin0o is 0, and the force is 0 N.

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