I have a voltage divider built from two resistors. The first resistor, R1, has a

Question

I have a voltage divider built from two resistors. The first resistor, R1, has a resistance of 7.00kO. The second, R2, has a resistance of 3.00kO. There is a voltage, Vin, of 12.00 volts applied across the two resistors in the divider. What is the current, in milliAmperes (mA), through the divider? What is the output voltage of the divider at R2? Enter all results to two numbers after the decimal point.

We are building a second divider. We want Vout to be one tenth of Vin. IF R1 is 18.00M, what resistance should R2 have?  (1.00M = 1.00x106) Enter all results to two numbers after the decimal point. 

Explanation / Answer

voltege divider for theory refer this link http://en.wikipedia.org/wiki/Voltage_divider now come to your ques you have two resistance connecting in series with voltage source and apply kvl or ohm's law , we get i*(3K+7K)-12=0 // since vin is 12.00 volt i=12/10 m amp i=1.20 m amp by voltage division rule : voltage across R2 = R2 * V/(R1+R2) VR2= 3K *12 /(3K+7K) VR2=3.60 volt now come to your second question voltage across R2 = R2 * V/(R1+R2) so now given VR2= Vin/10 = 1.2 volt so put all the values in above formula we get 1.2 = R2*12/(7+R2) 7+R2=10 R2=3 ohm

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