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A bob of mass M is at the end of a metal rod of length l and negligible mass. A

ID: 2008310 • Letter: A

Question

A bob of mass M is at the end of a metal rod of length l and negligible mass. A
bullet of mass m, initially moving with velocity v is shot through the bob. It comes out
with a velocity of v=2.
a) In terms of the above variables nd the velocity of the bob right after the collision.
b) What is the minimum value of v (again, in terms of the variables above) so that the
bob makes a full vertical circle.

and

 

A block of mass 1kg starts from rest and slides down a curved wedge of mass 6kg.
At the end of the slide, the block has a velocity of v1= 4m/s. Assume all surfaces are
frictionless.
a) What is the nal velocity of the wedge (once the block slides o)?
b) What is the original height of the wedge?

 

 

 

 

Explanation / Answer

Hi I can answer your second question: Its M1V1 + M2V2 = (M1+M2)v 9150kgx15m/s + 0 = (9150kg +4350kg)V so V = 10.166m/s

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