1. Draw neat schematics (using a ruler) of the three circuits used in this exper
ID: 2007963 • Letter: 1
Question
1. Draw neat schematics (using a ruler) of the three circuits used in this experiment. Label the points at which you will make measurements and indicate what kind of measurements they are. Show the meter polarity (where the positive and negative meter leads were used) for all measurements.
2. Derive the equations for the equivalent resistance of resistors in parallel and in series. What happens to the current as more resistors are added to a series circuit? to a parallel circuit?
3. Use Kirchhoff's laws to set up three simultaneous equations that can be solved for the value of each of the currents in Figure 3 in terms of the power supply voltages and the resistor values. Use the measured resistor and power supply voltage values to calculate the expected currents for the third circuit using the equations you derived. Compare the theoretical and experimental results.
4. Explain how a fuse works. Why is it extremely dangerous to put a too large a fuse in a circuit?
Please show me step by step and thank you so much for your help
Explanation / Answer
2. SERIES COMBINATION Let consider three resistors which have the resistances R1, R2 and R3 are connected in series with a battery. Let the current in the circuit is ' i ' and the voltage in the circuit is ' v '. Since the resistaors are in series the current passing through them is same.But the potential difference is different at each resistor and are given by v1, v2 and v3. We know from ohm's law, v = iR At first resistor, v1 = iR1 ; at second resistor, v2 = iR2; at third resistor, v3 = iR3 We know that v = v1 + v2 + v3 iR = iR1 + iR2 + iR3 So the resultant resistance of the series combination is R = R1 + R2 + R3 PARALLEL COMBINATION Let consider three resistors which have the resistances R1, R2 and R3 are connected in parallel with a battery. Let the current in the circuit is ' i ' and the voltage in the circuit is ' v '. Since the resistors are connected in parallel the current through them is different at each resistor and are given by i1, i2 and i3. The potential is same at all resistors. We know that, iR = v from the above, i = v/R So, i1 = v/R1, i2 = v/R2 and i3 = v/R3 But we have, i = i1 + i2 + i3 v/R = v/R1 + v/R2 + v/R3 1/R = (1/R1) + (1/R2) + (1/R3) So the resultant resistance of the parallel combination of the resistors is 1/R = (1/R1) + (1/R2) + (1/R3) PLEASE POST EACH PROBLEM SEPARATELY. THANq So the resultant resistance of the series combination is R = R1 + R2 + R3 PARALLEL COMBINATION Let consider three resistors which have the resistances R1, R2 and R3 are connected in parallel with a battery. Let the current in the circuit is ' i ' and the voltage in the circuit is ' v '. Since the resistors are connected in parallel the current through them is different at each resistor and are given by i1, i2 and i3. The potential is same at all resistors. We know that, iR = v from the above, i = v/R So, i1 = v/R1, i2 = v/R2 and i3 = v/R3 But we have, i = i1 + i2 + i3 v/R = v/R1 + v/R2 + v/R3 1/R = (1/R1) + (1/R2) + (1/R3) So the resultant resistance of the parallel combination of the resistors is 1/R = (1/R1) + (1/R2) + (1/R3) PLEASE POST EACH PROBLEM SEPARATELY. THANq Let consider three resistors which have the resistances R1, R2 and R3 are connected in parallel with a battery. Let the current in the circuit is ' i ' and the voltage in the circuit is ' v '. Since the resistors are connected in parallel the current through them is different at each resistor and are given by i1, i2 and i3. The potential is same at all resistors. We know that, iR = v from the above, i = v/R So, i1 = v/R1, i2 = v/R2 and i3 = v/R3 But we have, i = i1 + i2 + i3 v/R = v/R1 + v/R2 + v/R3 1/R = (1/R1) + (1/R2) + (1/R3) So the resultant resistance of the parallel combination of the resistors is 1/R = (1/R1) + (1/R2) + (1/R3) PLEASE POST EACH PROBLEM SEPARATELY. THANqRelated Questions
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