(A)A current of 1.65 A is flowing through a 1675 turn solenoid of length L = 31.

Question

(A)A current of 1.65 A is flowing through a 1675 turn solenoid of length L = 31.7 cm. What is the magnitude of the magnetic field inside the solenoid?

(B)A Helmholtz coil is used to generate a uniform magnetic field. Suppose the Helmholtz coil consists of two sets of coaxial wire loops with 15.0 turns of radius R = 79.1 cm, which are separated by R, and each coil carries a current of 0.131 A flowing in the same direction. Calculate the magnitude and the direction of magnetic field in the center between the coils.

Explanation / Answer

A. B =IN/L

   =4**10*^-7*1.65*1675/31.7*10^-2

   = 4*3.14*10^-7*1.65*1675 /(31.7*10^-2)

   = 34712.7*10^-7/31.7*10^-2

   = 1095 *10^-5 Tesla

still doing part B

hope thsi helps

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