The hammer throw is a track-and-field event in which a 7.8-kg ball (the \'\'hamm
ID: 2007477 • Letter: T
Question
The hammer throw is a track-and-field event in which a 7.8-kg ball (the ''hammer''), starting from rest, is whirled around in a circle several times and released. It then moves upward on the familiar curving path of projectile motion. In one throw, the hammer is given a speed of 26.0 m/s. For comparison, a .22 caliber bullet has a mass of 2.6 g and, starting from rest, exits the barrel of a gun with a speed of 409 m/s. Determine the work done to launch the motion of both the hammer and the bullet.Explanation / Answer
Work done W = change in k.e.
= Kf - Ki
since both hammer and bullet started from rest, Ki would be zero in both cases. hence
W = Kf = (1/2) * m * vf2
for the hammer Wh = (1/2) * 7.8 * 26.02
= 2.6364 * 103 J
for the bullet Wb = (1/2) * 2.6 * 10-3 * 4092
= 2.1746 * 102 J
I typed 103 in place of 102, my mistake.
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