The hammer throw is a track-and-field event in which a 7.1-kg ball (the \'\'hamm
ID: 2007415 • Letter: T
Question
The hammer throw is a track-and-field event in which a 7.1-kg ball (the ''hammer''), starting from rest, is whirled around in a circle several times and released. It then moves upward on the familiar curving path of projectile motion. In one throw, the hammer is given a speed of 30.0 m/s. For comparison, a .22 caliber bullet has a mass of 2.6 g and, starting from rest, exits the barrel of a gun with a speed of 409 m/s. Determine the work done to launch the motion of both the hammer and the bullet.(a) the hammer
(b) the bullet
Explanation / Answer
This is a simple problem kinetic energies, here work done is K.E It is said that initially both hammer and the bullet is at rest. Work done to launch the hammer = 1/2 mv2 Given, mass of hammer m = 7.1 kg velocity of the hammer v = 30.0 m/s Thus W = 0.5 * 7.1 kg* (30.0 m/s)2 = 3.19 * 103J Work done to launch the bullet = 1/2 mv2Given, mass of hammer m = 2.6 g velocity of the hammer v = 409 m/s Thus W = 0.5 * 2.6 kg* (409 m/s)2 = 2.17 * 102J
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