A brick is resting atop a piston that is moving vertically with simple harmonic
ID: 2007370 • Letter: A
Question
A brick is resting atop a piston that is moving vertically with simple harmonic motion of period 1.41 s.a) At what amplitude will the brick separate from the piston?
b) If the piston's amplitude is 4.92 cm, find the maximum frequency at which it can move without dislodging the brick.
A spring is suspended from a ceiling and has a block attached to its lower end. The block is held a distance y1 from the ceiling (at this point the spring is at its rest length) and released. The block oscillates up and down with its lowest point being 0.106 m below y1.
a) Find the frequency of the motion.
b) Calculate the speed of the block when it is 0.075 m below the release point at y1.
Explanation / Answer
Given 2) The amplitude of the block is, x = 0.106 m The force acting on the block is F = kx mg = kx k/m = g/x = 9.8 m/s^2 / 0.106 m k/m = 9.615 s-1 a) Frequency of the motion is f = /2 = (k/m ) / 2 f = 9.615 s-1 /6.28 f = 1.5 Hz b) If the amplitude A = 0.075 m, then the speed of the block is v = A = 0.075 m * 9.615 s-1 v = 0.72 m/s *post only one question for each post* a) Frequency of the motion is f = /2 = (k/m ) / 2 f = 9.615 s-1 /6.28 f = 1.5 Hz b) If the amplitude A = 0.075 m, then the speed of the block is v = A = 0.075 m * 9.615 s-1 v = 0.72 m/s *post only one question for each post*Related Questions
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