A straight rod moves along parallel conducting rails, as shown below. The rails

Question

A straight rod moves along parallel conducting rails, as shown below. The rails are connected at the left side through a resistor so that the rod and rails from a closed rectangular loop. A uniform field perpendicular to the movement of the rod exists throughout the region. Assume the rod remains in contact with the rails as it moves. The rod experiences no friction or air drag. The rails and rod haw negligible resistance. At what speed should the rod be moving to produce the upward current in the resistor? Answer in units of m/s. The rod is moving to the right. stationary. moving to the left. moving either left or right, since both directions produce the same result.

Explanation / Answer

The current in the resistance, i = 0.51 A The resistor, R = 8 The length between the rails, L = 0.87 m The magnetic field strength, B = 3.2 T The angle between the B and the velocity of rod is perpendicular.             So, = 90 deg The induced emf is = BLv sin                             IR = BLv sin From the above equation we get the formula for the velocity as                               v = IR / BL sin                                                                           =( 0.51A)(8 ) /(3.2T)(0.87m) sin900                                                           = 1.46 m/s So the speed of the rod should be 1.46 m/s                             IR = BLv sin From the above equation we get the formula for the velocity as                               v = IR / BL sin                                                                           =( 0.51A)(8 ) /(3.2T)(0.87m) sin900                                                           = 1.46 m/s So the speed of the rod should be 1.46 m/s

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