Rank the following ideal gases in order from highest to lowest temperature. a) 1

Question

Rank the following ideal gases in order from highest to lowest temperature. a) 1 mol of gas at pressure 2 atm occupying volume 1 L b) 1 mol of gas at pressure 1 atm occupying volume 2 L c) 2 mol of gas at pressure 1 atm occupying volume 1 L d) 2 mol of gas at pressure 1 atm occupying volume 2 L e) 1 mol of gas at pressure 1 atm occupying volume 1 L Rank the following ideal gases in order from highest to lowest temperature. a) 1 mol of gas at pressure 2 atm occupying volume 1 L b) 1 mol of gas at pressure 1 atm occupying volume 2 L c) 2 mol of gas at pressure 1 atm occupying volume 1 L d) 2 mol of gas at pressure 1 atm occupying volume 2 L e) 1 mol of gas at pressure 1 atm occupying volume 1 L

Explanation / Answer

From ideal gas equation R = 8.31J/mol.K and P = 2atm = 2(101*10^3 Pa) and V = 10^-3 m^3            PV= nRT then Ta = (2(101*10^3 Pa)) (10^-3) / 8.31             = 24 K when P = 1atm n = 1 and L = 2L          Tb = 24K when n = 2, P = 1atm and v = 1L         Tc = 6K when n = 2 , P =1atm and V = 2L          Td = 12K When n = 1, P = 1atm and V =1L           Te =   12K Now Ta = Tb > Td = Te > Tc

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