One strategy in a snowball fight is to throw a snowball at a high angle over lev

Question

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponet is watching the first one, a second snowball is thrown at a low angle timed to arrive before or at the same time as the first one. Assume both snowballs are thrown with a speed 25m/s. The first one is thrown at a angle 70* with respect to horizontal. a) At what angle should the second one be thrown to arrive at the same point as the first? b) How many seconds later should the second snowball be thrown after the first to arrive at the the same time?

Explanation / Answer

b) The time a snowball is in the air is 2tmax_height = 2vy0/g = (2v0sin0)/g. The flight time of the first snowball is 2tmax_height = 2v0sin70o/g = 4.79 s. The flight time of the second snowball is 2tmax_height = 2v0sin20o/g = 1.74 s. The second snowball must be thrown 3.05 s after the first ball.

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