After class, a physics student walks a distance of 22.3 meters in a direction of

Question

After class, a physics student walks a distance of 22.3 meters in a direction of 40 degrees north of east in 29.4 seconds. The student then walks a distance of 33.6 meters in a direction 15 degrees west of north in 40.2 seconds. The student then walks a distance of 28 meters in a direction of 38 degrees west of south in 30.2 seconds. finally, the student turns and walks a distance of 25.1 meters in a direction of 22 degrees south of east in 30.3 seconds. What is the average velocity of the student during his walking and what is the average speed that the student was moving?

Explanation / Answer

Average speed is a scalar quantity so direction is not needed. It equals the sum of all the distances divided by the times, divided by the number of distance/times. [(22.3/29.4)+(33.6/40.2)+(28/30.2)+(25.1/30.3)]/4 = (.759+.836+.927+.828)/4 = .8375m/s

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