the total mechanical energy at position A. the speed of the ball at position B a

Question

the total mechanical energy at position A. the speed of the ball at position B and the work done by friction from B to C if it comes to rest at Position C A 25.0 g bullet with an initial speed of 100 m/s strikes and lodges in a 5 kg ballistic pendulum that is initially at rest, What is the speed of the combined bullet pendulum after the collision bullet How high will the pendulum rise? Billiard ball 2 is at rest when it is hit with collision by ball 1 moving it a velocity of 50.0 cm/s towards he right. After the collision ball 1 moves off at an angle of 40.0degree as shown in Fig. 4. The mass of each billiard ball is 0.17 Eg: a) Find the velocity of each ball after collision and Find the kinetic energy before and after collision. Is the collision elastic?

Explanation / Answer

Mass of the bullet m1 = 0.025kg Mass of the ballistic pendulum m2 = 5 kg initial velocity of the bullet u1 = 400 m/s initial velocity of the ballistic pendulum u2 = 0.0 m/s final velocity of the combined system V (a)since it is inelastic collision According to conservation of linear momentum m1 u1   + m2u2 = (m1 + m2)V plging all the values we get final velocity of the system V = 1.99   m/s ˜ 2 m/s (b) applying conservation of energy bullet and block system after collision (1/2) (m1 + m2) V^2 = (m1 + m2)gh solving for height   h = sqrt *( V^2 / 2g) Her V = 2 m/s , g = accelaration due to gravity = 9.8 m/s^2 h = 0.20 m please post remaining as another question

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