Suppose that autosomal dominant polycystic kidney disease (ADPKD) affects 1 in 7

Question

Suppose that autosomal dominant polycystic kidney disease (ADPKD) affects 1 in 750 individuals in the human population. Question 33 (1 point) What is the frequency of the non-disease allele in the human population? (Please write your answer to four decimal places) Save Question 34 (1 point) What is the frequency of the ADPKD allele in the human population? (Please write your answer to four decimal places) Save Question 35 (1 point) What is the frequency of heterozygous individuals in the population? (Please write your answer to four decimal places) Save Question 36 (1 point) e Whole Words 1 of 5 matches

Explanation / Answer

ADPKD = Dominant = AA or Aa will show mutant phenotype.

Frequency ADPKD = 1/750 = 0.00133

p2 + 2pq = 0.00133

p2 + 2pq + q2 = 1

q2 = 1 - 0.00133

q2 = 0.99867

Frequency of WT allele, q = 0.99933477874

p+q = 1

p = 1 - 0.99933477874

Frequency of ADPKD allele, p = 0.000665

Frequency of heterozygous individuals, 2pq = 2 X 0.000665 X 0.99933477874

= 0.001329

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