A light ray traveling in air is incident on the top surface of water in an open

Question

A light ray traveling in air is incident on the top surface of water in an open glass fish tank. The ray reflected from the water surface is completely polarized. The index of refraction of water is 1.33; the index of refraction of the glass in the fish tank is 1.52. Find the angle of incidence of the light ray. the angle of reflection of the reflected ray and the angle of refraction of Die ray that is refracted into the tank of water. Make a sketch showing the air-water boundary, the incident light ray. the reflected light ray and the refracted light ray of pan a. In your sketch identify the angle of incidence, the angle of refraction and the angle of reflection In the sketch you made in pan b extend the refracted ray so that it strikes a vertical glass wall of the fish tank. Docs any part of this ray make it out into the air outside the glass wall? Explain and justify your answer with appropriate calculations.

Explanation / Answer

   concept: When the light is incident on the top of the surface of the    water and some part of this ray will refrated in to water and remaing part of light is reflected from the surface of the water let, i be the icident angle of light on the water surface           r be the refracted angle in to glass    form , snell law , we have              nW sin i = nG sin r               where refractive -index of water =   nW = 1.33                           refractive -index of glass = nG   = 1.52                        but, we have , i + r = 90o                 Thus,   (1.33)   sin i   = (1.52) sin r                    (1.33)   sin i   = (1.52) sin (90-i)                                       i   = 48.81o                        Thus, angle of refraction is   : r = 90o - 48.81o                                                                    r = 41.18o                            since, some part of light is refleted from the surface of the water                     the angle of incidence is equal to angle of reflection                          thus, angle of reflection is =48.81o                     Thus,                       Angle of incidence = i = 48.81o                            Angle of reflection = 48.81o                            Angle of refraction = r =  41.18o      Part (a) is so helpful to u            Plz. post remaning seperetely..,

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