In soreflies (a hypothetical insect), the dominant allele, L , is responsible fo
ID: 200518 • Letter: I
Question
In soreflies (a hypothetical insect), the dominant allele, L, is responsible for resistance to a common insecticide called Loritol. Another dominant allele, M, is responsible for the ability of soreflies to sing like birds. A true-breeding mute, Loritol-resistant sorefly was mated to a true-breeding singing, Loritol-sensitive sorefly, and the singing, Loritol-resistant female progeny were test-crossed with true-breeding wild-type (i.e., mute, Loritol-sensitive) males. Of the 400 total progeny produced, 117 were mute and Loritol-resistant, 114 could sing and were Loritol-sensitive, 83 could sing and were Loritol-resistant, and 86 were mute and Loritol-sensitive. What will be the results of a chi-square test for independent assortment using a contingency table?
A. 6.48 with four degrees of freedom
B. 9.1 with one degree of freedom
C. Because there are four classes of offcspring, the genes must be assorting independently.
D. 4.63 with three degrees of freedom
E. 2.54 with one degree of freedom
In soreflies (a hypothetical insect), the dominant allele, L, is responsible for resistance to a common insecticide called Loritol. Another dominant allele, M, is responsible for the ability of soreflies to sing like birds. A true-breeding mute, Loritol-resistant sorefly was mated to a true-breeding singing, Loritol-sensitive sorefly, and the singing, Loritol-resistant female progeny were test-crossed with true-breeding wild-type (i.e., mute, Loritol-sensitive) males. Of the 400 total progeny produced, 117 were mute and Loritol-resistant, 114 could sing and were Loritol-sensitive, 83 could sing and were Loritol-resistant, and 86 were mute and Loritol-sensitive. What will be the results of a chi-square test for independent assortment using a contingency table?
A. 6.48 with four degrees of freedom
B. 9.1 with one degree of freedom
C. Because there are four classes of offcspring, the genes must be assorting independently.
D. 4.63 with three degrees of freedom
E. 2.54 with one degree of freedom
Explanation / Answer
B. 9.1 with one degree of freedom
the results of a chi-square test for independent assortment using a contingency table would be 9.1 with one degree of freedom.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.