An OSU engineering student constructs a simple clock by tying the top of a piece

Question

An OSU engineering student constructs a simple clock by tying the top of a piece of string to an immovable post and attaching her cell phone to the bottom of the piece of string. She displaces the cell phone to the right so that the string makes an angle of 10.0 degrees with the vertical and releases it. The cell phone swings back and forth with simple harmonic motion. The mass of the cell phone is 125grams and the period of oscillation is 2.00 seconds. What is the distance from the post to the center of mass of the cell phone.

Explanation / Answer

The period of the oscillation of pendulum is T = 2 s As the pendulum is in simple harmonic motion, the period of the pendulum is independent size and shape of the pendulum and is given by T = 2(L/g) L = gT2/42 L = (9.8 m/s2)(2 s)2/42 L = 0.994 m L = (9.8 m/s2)(2 s)2/42 L = 0.994 m

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