A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as

Question

A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as functions of time are given by x = 18.21 and y = 3.76t - 4.90t^2, where x and y are in meters and t is in seconds. Write a vector expression for the ball's position as a function of time, using the unit vectors l and J. (Give the answer in terms of t.) By taking derivatives, do the following. (Give the answers in terms of t.) (b) obtain the expression for the velocity vector v as a function of time obtain the expression for the acceleration vector a as a function of time Next use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the golf ball at t = 2.85 s.

Explanation / Answer

Ans:

a) r = 18.2ti + (3.76t - 4.90t2)j m

b) v=(dr/dt) = 18.2i + (3.76 - 9.8t)j m/sec

c) a=(dv/dt) = -9.8j  m/sec2

d) at t=2;

r = 51.87i - 29.08j m

v = 18.2i - 24.17j m/sec

a = -9.8j  m/sec2

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