You have built a device that measures the temperature outside and displays it on

Question

You have built a device that measures the temperature outside and displays it on a dial as a measure of how far away from room temperature outside is. The way the dial works is that a needle with a charged ball on the end is placed between two charged parallel plates. The strength of the uniform electric field between the plates is proportional to the outside temperature. Given that the charged ball on the needle has a charge of 2.25 µC and the needle can be represented as a string with tension 0.350 N, and is at an angle of 25°, consider the following.

What is the mass of the object?

=____ g

What is the magnitude of the electric field?

=____ N/C

Explanation / Answer

Balancing the forces in x- direction , we have

qE = T sin theta ---------(1)

substituting the values in (1) we have

2.25*10^-6*E = 0.35* sin 25

E = 65740 N/C

Balancing the forces in y-direction , we have

mg = T cos theta --------(2)

m*9.8 = 0.35*cos 25

m = 0.032 kg

mass of the object = 0.032 kg = 32g

magnitude of the electric field = 65740 N/C

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