How do you arrive to the given answers? What is the setup for this type of probl

Question

How do you arrive to the given answers? What is the setup for this type of problem?

3. (10 mutant 2. Mutants 3 Points) Mutant s l and 2 are two point mutations of rlIA. Mutant 1 does not overlap with and 4 are two deletion mutations of rIIB. Mutant 3 overlaps with mutant 4 a deletion that overlaps mutants 2 and 4, but does not overlap mutants 1 and 3,. For each of the follo infection on E. coli strain K Finally, you dilute this second lysate and perform low m.o.i infections o coli B and E. coli K. n separate plates with E Predict the results by circling ONE answer per cross. Select "Equal Number" if the E. coli B and K plates will have some plaques in equal proportions; select "No Plaques" if both plates show O plaques; select "Can't tell" if the information provided is insufficient to predict the E. coli will result with certainty Can't tell 1 x 2 More on E coli B Equal Number No Plaques 1x3 More on E coli B ) Equal Number NoPlaques 2x4 More on E coli B Equal Number No-Plaques Can't tell . Can't tel Can't tell More on E coli B Equal Number No Plaques 3 x4 Can't tell 4 x 5 More on E coli B Equal Number No Plaques

Explanation / Answer

Ans-

E. coli B allows both to grow (mutant rIIA & rIIB)

E. coli K(), does not permit the growth of rII mutant but it does allow wild-type phages to grow

rIIA, rIIB cistrons -complementing mutation

Mutation 1,2 (point mutation)- present on rIIA & Mutation 3, 4(deletion mutation) on rIIB

So, based on this information we can find out the-

1X2         -              Equal number ( because rIIB is wild-type which helps to grow E.coli K)

1x3         -              E.cloi only (because rIIA and rIIB both mutant)

2x4         -              E.coli only

3x4         -              Equal

4X5         -              E.coli only (because mutant 5 is deletion mutant which overlaps with 2and 4)

Note- Phage will grow in E.coli K only when rIIA & rIIB, one of these is wild-type

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