2. The fraggles are a population of mythical, mouselike creatures that live in u

Question

2. The fraggles are a population of mythical, mouselike creatures that live in undergrown tunnels and chambers beneath a large vegetable garden that supplies their food. Of the fraggles currently in this population, 372 have green fur and 182 have gray fur. Green fur is controlled by a dominant allele F and gray fur by a recessive allele f a) What is the frequency of the gray allele f 182/554-573 b) What is the frequency of the green allele F71-.573 = .427 c) How many fraggles are heterozygous (F)? 2(.427.573) x 554 271 Ff DELL B.

Explanation / Answer

Q) In this question the Number of fraggles that are having Green fur (it is homozygous ) characterised by 'F' genotype which is dominant = 372

The number of Fraggles having Grey fur (homozygous ) characterized by 'f' genotype which is recessive = 182

so total number of fraggles found in that area = F + f = 372+182= 554

p = the frequency of the dominant allele (here it is represented by F)
q = the frequency of the recessive allele (here it is represented by f)

For a population in genetic equilibrium:

p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)

(p + q)2 = 1

so
p2 + 2pq + q2 = 1

The three terms of this binomial expansion shows the frequencies of three genotypes:

p2 = genotype frequency of FF (homozygous dominant)
2pq = genotype frequency of Ff (heterozygous)
q2 = genotype frequency of ff (homozygous recessive)

Here in this problem we need to calculate the number of heterozygous individuals = it will be 2*p*q* total number of individuals.

Number of heterozygous individuals (Ff ) = { 2 * Frequency of dominant allele (p) * Frequency of recessive allele (q) * Total number of individuals }

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