Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

oooo Verizon 4:31 PM 3396 . session.masteringphysics.com C Phy 201 Spring 2016 N

ID: 2001732 • Letter: O

Question

oooo Verizon 4:31 PM 3396 . session.masteringphysics.com C Phy 201 Spring 2016 Night Problem 33 Rewarkter fer Practice A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. Part A If the plane is traveling horizontally with a speed of 238 km/h (66.1 m/s), how far in advance of the recipients (horizontal distance) must the goods be dropped (see the figure (a))? z458 m Submit My Answers Give Up Correct Part B Suppose, instead, that the plane releases the supplies a horizontal distance of 425 m in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climbers' position (see the figure (b))? 504 m/s Submit My Answers Give Up Correct Part C With what speed do the supplies land in the latter case? e- 949 ms Submit All attempts used; correct answer displayed My Answers Give Up

Explanation / Answer

c)

Y = distance travelled in downward direction = height of plane = 235 m

Vo = initial velocity of launch of supplies = sqrt ((-5.04)2 + 66.12) = 66.3 m/s

Vf = final velocity

a = 9.8 m/s

Using conservation of energy

KE + PE at Top = KE at bottom

(0.5) m Vo2 + mgY = (0.5) m Vf2

(0.5) Vo2 + gY = (0.5) Vf2

(0.5) (66.3)2 + (9.8) (235) = (0.5) Vf2

Vf = 94.9 m/s