What fraction of offspring of the cross AaBb × aabb are expected to be homozygou

Question

What fraction of offspring of the cross AaBb × aabb are expected to be homozygous for the recessive allele at both loci (aabb), assuming that they are on different chromosomes? 1/4 1/8 1/32 1/16 1/64

Whether a seed is round or wrinkled is due to a single Mendelian gene, with the allele for round seeds being dominant to the allele for wrinkled seeds in heterozygotes. In the F2 progeny of a monohybrid cross, which are a product of self-fertilization in heterozygotes, _______ of 100 seeds should be wrinkled. 0 100 25 50 75

Explanation / Answer

1) AaBb × aabb

aabb = 4 / 16 = 1/4

Answer : 1 / 4

2) Rr x Rr

3 / 4 = round (RR, Rr)

1 / 4 = wrinkled (rr)

Out of 100 seeds :

(1 / 4) x 100 = 25 seeds are wrinkled

AB Ab aB ab ab AaBb Aabb aaBb aabb ab AaBb Aabb aaBb aabb ab AaBb Aabb aaBb aabb ab AaBb Aabb aaBb aabb

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