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ID: 2000637 • Letter: P
Question
physics question x New Tab x New Tab x New Tab X Jacob ty of C /ibiscms/mod/ibis/view.php?id-2469877 WWW. Saplinglea rning com E: Apps UCHC Candid Sel... s one Card office D This week's Menus O Best Medical School... IBb My Courses Black... University of Conne... P MyLab & Mastering O 26/2016 11:00 PM A 91/100 /25/2016 10:12 PM Assignment Information Gradebook Attempts Score dic Tab Print Calculator Available From: 8/2016 06:00 PM uestion 12 of 12 Incorrect 26/2016 11:00 PM Due Date: Map 99 Points Possible 100 98 Grade Category: Graded A 15.91-mC cha Description: est at a distance 32.53 cm above e right-most charge. If the particle were to be released from rest, it would follow some complicated path around the two stationary Policies: Homework charges Calculating the exact path of the particle w uld be a cha ging probl m, but e n without such a calculation it is possible to make some definite predictions about the future motion of the heck y particle You can view solutions when vou complete or give If the path of the particle were to pass through the gray point labeled what would be its speed vA at up on any question 95 that point? -4.551 AC You can keep trying to answer each question until you get it right or give up 31.88 You lose 5% of the points available to each answer in your question for each incorrect attempt at that 32.53 cm +15.91 mC O eTextbook K- 10.85 cm l +81.73 mC O Help With This Topic 36.15 cm O Web Help & Videos ncorrect O Technical Support and Bug Reports Try Again ONex Give Up & Vi Exp /26/2016Explanation / Answer
Electric PE between a point charge pair = -kq1q2/d
so initially,
PE of system = PE of -4.55uc and 15.91mC + PE of -4.55uc and 81.73mC
and relative position ofg 36.15 and 81.73uC charges is not changing.
so we will find deltaPE so it will ge cancel.
so no need to find it. ( we will call it P1)
PEi = - [(9e9 * 81.73e-3 * 4.551e-6) /(0.3253)] -[(9e9 * 15.91e-3 * 4.551e-6) /sqrt(0.3253^2 +0.3615^2)]
PEi = -10290.74 - 1340 + P1 = - 11630.73 + P1 J
final energy
PEf = -[(9e9 * 81.73e-3 * 4.551e-6) /(0.3615-0.1085)] - [(9e9 * 15.91e-3 * 4.551e-6) /0.1085]
= -13231.54 - 6006.06 + P1 = -19237.60 + P1 J
initial PE + KE = final PE + KE
- 11630.73 + P1 + 0 = -13231.54 - 6006.06 + P1 + (35.81 x 10^-3 x v^2 /2 )
35.81 x 10^-3 x v^2 /2 = 7606.87
v = 651.80 m/s
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