× GChegg Study Guided Sol× MInbox (779) Jacob hudob × Grant@Heart-Login x \"Expe

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× GChegg Study Guided Sol× MInbox (779) Jacob hudob × Grant@Heart-Login x "Experiment 1-Melting po -University of Connecticut C f Li www.saplinglearning.com/ibiscms/mod/ibis/view.php?id=2469877 :: Apps a UCHC Candidate Sel $ One Card Office D This week's Menus OBest Medical School. My Courses-Black . University of Conne DMyLab & Mastering 1/26/2016 11:00 PM A 89/100 1/25/2016 10:12 PM Assignment Information Available From 1/18/2016 06:00 PMM Due Date: Points Possible: Grade Category: Graded Description: Policies: # Attempts Gradebook Print Calculator Periadic Table 100 Question 2 of 12 1/26/2016 11:00 PM 75 presanted by Mapoob UNIVERSITY PHYSICS Philip R. KestenDavid L. Tauck 100 sapling leaming 98 A red blood cell typically carries an excess charge of about-2.5 x 10-12 C distributed uniformly over its surface. The red blood cells can be modeled as spheres approximately 7.6m in diameter and with a mass of 9.0 x10-14 kg. How many excess electrons does a typical red blood cell have? 100 omework 100 1.5625 x 10electrons You can check your answers. ou can check your answers 100 You can view solutions when you complete or give up on any question. affect the mass of the cell? To find out, calculate the ratio Does the mass of the extra electrons a of the mass of the extra electrons to the mass of the cell without the excess charge 95 You can keep trying to answer each question until 100 you get it right or give up. 1.57x 10 You lose 5% of the points available to each answer in your question for each incorrect attempt at that answer 100 What is the surface charge density on the red blood cell? Express your answer in units of C/m2 and electrons/m2 100 eTextbook 4.97 x 10 C/ m D Help With This Topic Number Incorrect. Web Help &Videos; 16 8.63 × 1 0 electrons/ m Previous Give Up & View Solution # Try Again Technical Support and Bug Reports Next Exit Explanation 9:47 AM 1/26/2016

Explanation / Answer

here,

diameter of cell , d = 7.6 um

radius , r = 3.8 um

r = 3.8 * 10^-6 m

charge q = - 2.5 * 10^-12 C

surface charge density , p = charge /surface area

p = -2.5 * 10^-12 /( 4 * pi * ( 3.8 * 10^-6)^2)

p = - 1.38 * 10^-2 C/m^2

or

p = - 1.38 * 10^-2 /( 1.6 * 10^-19) electrons /m^2

p = 8.63 * 10^16 electrons/m^2

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