In one of the classic nuclear physics experiments at the beginning of the 20th c

ID: 1999370 • Letter: I

Question

In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward a gold nucleus, and its path was substantially deflected by the Coulomb interaction. If the energy of the doubly charged alpha nucleus was 5.00 MeV, how close to the gold nucleus (79 protons) could it come before being deflected What is the potential between two points situated 10 cm and 20 cm from a 3.0 Mu C point charge To what location should the point at 20 cm be moved to increase this potential difference by a factor of two

Explanation / Answer

33. charge on alpha particle = 2e

initial KE of alpha = 5 MeV

as it goes close to nucleus than its potential energy will increase and KE will decrease.

and finally KE will become zero and PE will max.

so when KE = 0

initial KE = final PE

5 x 10^6 x 1.6 x 10^-19 J = (kQq / d)

5 x 10^6 x 1.6 x 10^-19 = (9 x 10^9 x 79 x 1.6 x 10^-19 x 2 x 1.6 x 10^-19) / d

d = 4.55 x 10^-14 m

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In one of the classic nuclear physics experiments at the beginning of the 20th c

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