A student set up the magnetic optical bench as shown. The locations of the compo

Question

A student set up the magnetic optical bench as shown. The locations of the component holders for the crossed arrow target (CAT), and screen (S), are as follows, respectively: 228 mm, 825 mm The offsets for the CAT and the S are 4.00 mm, and the offset for lens, L is 6.00 mm. The inverted image formed on the screen is 0.750 times the size of the object. What is the position of the CAT on the optical bench? What is the position of the S on the optical bench? Calculate the position of the component holder of the lens? What is the position of the L on the optical bench? Calculate the object distance from the lens. Calculate the image distance from the lens, Calculate the focal length of the lens. Without changing the CAT and the S location, calculate position where would you place the component holder of the lens to obtain an inverted image that is 1.65 times size of the object?

Explanation / Answer

a) position of CAT on optical bench = 228-4 =224 mm

b)position of S on optical bench = 825+4 =829 mm

c) Lens holder location = 224+ (829-224)*1/1.75 +6 = 575.7 mm)

d) position L = 575.7-6 = 569.7 mm

e) object distance = 569.7-224 = 345.7 mm

f)image distance = 829-569.7 = 259.3 mm

g) -1/u + 1/v = 1/f

1/345.7 + 1/259.3 = 1/f

f = 345.7*259.3/(345.7+259.3) = 148.2 mm

h) L = 224+(829-224)*1/(1+1.65) +6 = 458.3 mm

  

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.