A spring with a mass attached to it oscillates on a frictionless, horizontal sur

Question

A spring with a mass attached to it oscillates on a frictionless, horizontal surface. The spring has a constant of k = 75.5 N/m. The mass has a mass of m = 0.220 kg. We can treat the spring as massless. The spring is stretched (take that to be the positive x direction) d = 5.00 cm and then released. We start a stopwatch when the spring is unstretched and the mass is moving in the positive direction.

a) If we cast the solution in the standard form, x(t) = A cos(t + ), what is A in cm?

b) what is = phi in radians?

Explanation / Answer

Here ,

k = 75.5 N/m

w = sqrt(k/m)

w = sqrt(75.5/0.220)

w = 18.53 rad/s

also , as the initial stretch , A = 5 cm

a) x(t) = 5 * cos(18.53 * t) cm

b) the value of phi is 0 radian

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