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Question

Mae creo Cole x e 404 Red x creo 30 x Facebook x x D spr-mass x Mail- Ro x shut up x G how tota x Ronnie Creo 3.0 X Take Te /webapps/assessment/take/launchjsp?course assessment id 418452 1&course; id 212084 18 content id 11843605 18step null https://ct-ccsu.blackboard.com 1 points Save Answer QUESTION 1 A mass M 1.0 kg rests on a horizontal rough surface is attached to two identical unstressed horizontal springs A and B, at right angles to each other as shown in the figure 3. The other end of each spring is attached to a friction less roller that always in contact with the track as shown in the figure spr-mass.pdf. The coefficient of friction between the mass and the horizontal surface is 0.5. Two perpendicular forces, FYand Fxof variable magnitude simultaneously act on the mass M such that the mass moves very slowly along a straight line from its initial to final location which is 3.0 cm along the x-axis and 4.0 cm along the axis. Take acceleration due to 10 m/s2 gravity. Find the maximum frictional force in Newtons Page 4 QUESTION 2 1 points Save Answer Mechanical work converted to heat energy in Joules 1 points Save Answer QUESTION 3 Find the maximum value of Fxin N Show a x pd spr-ma 2:15 PM 11/17/2016

Explanation / Answer

1)Maximum friction force = umg = 0.5×1×10

= 5 N

2) work converted to heat = 5N× 0.05m

= 0.25 J

3) Fx*0.04 + Fy*0.03 = 0.25 + 0.5×100×0.04^2 × 0.5×100×0.03^2

= 0.2536 J

Also by symmetry Fx = 4/3 Fy

0.04 Fx + 0.03×3/4Fx = 0.2536

Fx = 0.2536/0.0625

= 4.0576 N

B) Fy = 0.75* Fx = 3.0432 N

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