A very light rigid rod with a length of 0.429 m extends straight out from one en

Question

A very light rigid rod with a length of 0.429 m extends straight out from one end of a meter stick. The combination is suspended from a pivot at the upper end of the rod as shown in the following figure. The combination is then pulled out by a small angle and released. Determine the period of oscillation of the system. By what percentage does the period differ from the period of a simple pendulum 0.929 m long? Your response differs from the correct answer by more than 10%. Double check your calculations.

Explanation / Answer

In part 1

T = 2 sec

Part 2

T = 2*pi*sqrt (l/g)

l = 0.929 m

T = 2*pi*sqrt (0.929/9.80) = 1.934 sec

Percentage change = (2 - 1.934)*100/2 = 3.3%

Comment below if you have any doubt.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.