1. Find the maximum possible coefficient of performance for a heat pump used to

Question

1. Find the maximum possible coefficient of performance for a heat pump used to heat a house in a northerly climate in winter. The inside is kept at 23 C while the outside is -20 C COPmax=____________

2. Air conditioners sold in the United States are given a seasonal energy-efficiency ratio (SEER) rating that consumers can use to compare different models. A SEER rating is the ratio of heat pumped to energy input, similar to a COP but using English units, so a higher SEER rating means a more efficient model. You can determine the COP of an air conditioner by dividing the SEER rating by 3.4.For inside temperature 26 C and outside temperature 30 C when you'd be using air conditioning, estimate the theoretical maximum SEER rating of an air conditioner. (New air conditioners must have a SEER rating that exceeds 13, quite a bit less than the theoretical maximum, but there are practical issues that reduce efficiency.) SEERmax=___________

Explanation / Answer

1) Assuming maximum efficiency

COP = ( T1 ) / ( T1 - T2 )

= 296 / (296 - 253)

= 6.88

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2) COP COPmax = Tcold (Thot - Tcold)

For air conditioner

COPmax = (273 + 26) / (4) = 74.75

SEER rating is 3.4 times the COP

SEERmax = 3.4 * COPmax = 3.4 * 74.75

SEERmax = 254

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